0=4.8t^2-4t

Solution for 0=4.8t^2-4t equation:

0=4.8t^2-4t

We move all terms to the left:

0-(4.8t^2-4t)=0

We add all the numbers together, and all the variables

-(4.8t^2-4t)=0

We get rid of parentheses

-4.8t^2+4t=0

a = -4.8; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-4.8)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-4.8}=\frac{-8}{-9.6}
=8/9.6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-4.8}=\frac{0}{-9.6}
=0
$